2[s+3(s-1)]=18s

Solution for 2[s+3(s-1)]=18s equation:

Simplifying
2[s + 3(s + -1)] = 18s

Reorder the terms:
2[s + 3(-1 + s)] = 18s
2[s + (-1 * 3 + s * 3)] = 18s
2[s + (-3 + 3s)] = 18s

Reorder the terms:
2[-3 + s + 3s] = 18s

Combine like terms: s + 3s = 4s
2[-3 + 4s] = 18s
[-3 * 2 + 4s * 2] = 18s
[-6 + 8s] = 18s

Solving
-6 + 8s = 18s

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-18s' to each side of the equation.
-6 + 8s + -18s = 18s + -18s

Combine like terms: 8s + -18s = -10s
-6 + -10s = 18s + -18s

Combine like terms: 18s + -18s = 0
-6 + -10s = 0

Add '6' to each side of the equation.
-6 + 6 + -10s = 0 + 6

Combine like terms: -6 + 6 = 0
0 + -10s = 0 + 6
-10s = 0 + 6

Combine like terms: 0 + 6 = 6
-10s = 6

Divide each side by '-10'.
s = -0.6

Simplifying
s = -0.6